Absolute position of a row?

Is it possible to get the absolute left,top position of a grid row?

There are two internal method which could help - AW.left(element) and AW.top(element), the argument should be DOM node, i.e.

var top = AW.top(grid.getRowTemplate(rowIndex).element());

or for the extended grid

var top = AW.top(grid.getRowTemplate(rowIndex, 0).element());

Thanks Alex but I got an 'unknown method' for AW.top?

Anyway this returned the top value I was looking for:

var ypos = 0;
var gridrow = itsGrid.getRowTemplate(row).element();
while (gridrow != null)
{
  ypos += gridrow.offsetTop;
  gridrow = gridrow.offsetParent;
}

Which is probably similar to the 'top' method?

:-(

sorry, it should be AW.getTop(element) and AW.getLeft(element).

IE:

AW.getLeft = function(element){
    return element.getBoundingClientRect().left;
};

AW.getTop = function(element){
    return element.getBoundingClientRect().top;
};

Firefox:

AW.getLeft = function(element){
    var doc = document.getBoxObjectFor(document.body);
    return document.getBoxObjectFor(element).screenX - doc.screenX + doc.x;
};

AW.getTop = function(element){
    var doc = document.getBoxObjectFor(document.body);
    return document.getBoxObjectFor(element).screenY - doc.screenY + doc.y;
};

Your code will also work most of the time but it is less reliable in some extreme cases due to the offsetParent bugs.

Thanks Alex.